Tag Archives: revision

Primary 4 SA1 Revision 5

P4-SA1-Ex 5

Ans:

1–  Twelve thou­sand, seven hun­dred and ninety-eight

2–  2568

3–  1885 / 1886 /1887 /1888/1889/1891/1892/1893/1894

4–  5/9

5–  875

6–  761

        761          ,        12 870     ,     24 969      ,     37 058    ,    49 137
( +12 109)     (+ 12 099)      (+ 12 089 )     (+ 12 079)

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Primary 6 SA1 Revision 10

P6-SA1-Ex 10

Ans:

1–  3

2–  3

3–  4

2u –> 18 cm

1u –>  9 cm

Length –>  9 cm × 3u = 27 cm

Perime­ter –>  (18 + 27) cm × 2 = 90 cm

 

4–  2

5–  2

6–  3

Frac­tion of remain­ing cake –> 5/6

5/6 ÷ 1/12 = 10 pupils

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Primary 6 April Problem Sums 5

P6-PSP-Apr-Ex 5

Ans:

1–  30 m

Spaces between 100 trees –> 99

Dis­tance between each tree –> 297 m ÷ 99 = 3 m

3 m × 10 spaces = 30 m

 

2–  28 pupils

Num­ber of pupils who passed one or both sub­jects –> 40 — 2 = 38

30 + 36 = 66

66 — 38 = 28 pupils

 

3–  a ->  (18s + 24) kg ,   b ->   16 kg

Mass of chicken –>  3s kg

Mass of puppy –>  (3s + 4) kg

Mass of dog –>  (3+ 3s + 4) kg × 2 = (12+ 8) kg

3s + 3s + 4 + 12s + 8 = (18s + 12) kg                   (a)

18 × 2 + 12 = 48 kg

48 kg ÷ 3 = 16 kg                           (b)

 

4–  $51.30

Total cost of 5 apples and 5 man­goes –>  $3.25 × 5 = $16.25

Cost of 3 apples –>  $17.60 — $16.25 = $1.35

Cost of 1 apple –> $1.35 ÷ 3 = $0.45

Cost of 1 mango –> $3.25 — $0.45 = $2.80

Cost of 2 man­goes and 7 apples –>  $2.80 × 2 + $0.45 × 7 = $8.70

$50 — $8.70 = $51.30

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Primary 4 March Problem Sums 5

P4-PSP-Mar-Ex 5

Ans:

1–  $96

2–  28 sweets

Qn 2

If 1 add 12 more sweets to Jacque­line, she will have 1 unit.

4u –>  100 + 12 = 112

112 ÷ 4 = 28 sweets

 

3–  a ->  $8250   b ->  $2475

Amount of money Melanie spent in Jan­u­ary –>  $825 × 2 = $1650

$1650 × 5 = $8250          (a)

$825 + $1650 = $2475      (b)

 

4–  5/8 m

5– 1175 stamps

Roger –> 1u

Joshua –> 4u

4u — 1u = 3u

3u –>  705 stamps

1u –>  235 stamps

235 × 5u = 1175 stamps

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Primary 3 March Review 4

P3-Mar-Review 4

Ans:

1–  3

2–  2

3–  1

4–  1

5–  3

6–  2

7–  4

Num­ber of stamps Javier had –>  135 × 6 = 810

810 + 135 = 945 stamps

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Primary 6 March Review 7

P6-Mar-Review 7

Ans:

1–  3

2–  4

3–  4

3.30 p.m. to 4.30 p.m. –>  1st hour –> $3.50

4.30 p.m. to 5.45 p.m.–>  1 h 15 min ->  3 sets of half-hours
->  3 × $1 = $3

$3.50 + $3 = $6.50

 

4–  1

5–  2

6–  3

7–  2

75% — 50% = 25%

25% –>  105 ml

50% –>  105 ml × 2 = 210 ml

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Primary 5 March Review 3

P5-Mar-Review 3

Ans:

1–  3

2–  3

4  1/4 = 17/4

17/4 = 34/8

 

3–  4

4–  2

Length of String Q –>  3  1/5 m —  1  2/3 m = 1  8/15 m

1  8/15 m + 3  1/5 m = 4  11/15 m

 

5–  2

Remain­ing pizza after Joseph had eaten it –>  8/8 — 1/8 = 7/8

4/5 × 7/8 = 7/10

 

6–  1

Breadth of rec­tan­gle–>  (48 cm÷ 2) — 14 cm = 10 cm

14 cm × 10 cm = 140 cm²

 

7–  2

8–  2

(24 sweets  cost the same as 18 choco­lates )  ÷ 3

8 sweets cost the same as 6 chocolates

18 — 6 = 12 choco­lates 

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Primary 4 February Review 5

P4-Feb– Review 5

Ans:

1–  4

2–  4

3–  2

1 whole –>   4 quarters

4 quar­ters × 3 = 12 quar­ters

 

4–  3

5–  2

4 = 36/9

38/9  -  36/9  =  2/9

 

6–  2

7–  2

Sharon’s mass ->  (64 — 8)/2 = 28 kg

Susan’s mass 28 kg + 8 kg = 36 kg

28/36  =  7/9

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Primary 3 CA1 Revision 5

P3-CA1-Ex 5

Ans:

1–  6854

2–  2664

3– 2790

4–  8791

5–  4000

6480 — 2394 = 4086

80 + 6 = 86

4086 — 86 = 4000

 

6–  9731

8731 + 1000 = 9731

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Primary 6 Algebra Level 2 Ex 5

P6-Algebra-L2-Ex5

Ans:

1–  $(7y/2) /  $3.50y

Price of 1 durian –>  $(y/10)

$(y/10) × 35 = $(7y/2)/ $3.50y

 

2–  55

3–  (35 

4–  (4+ 10) years old

Brother’s age –>  3n + 9 — 2n = (n + 9) years old

Total age now –>  3n + 9 + n + 9 = 4n + 18 years old

4n + 18 – 4 – 4 = (4n + 10) years old

 

5–  $(m – 20)/3

6–  4.5z² cm²

Area of Tri­an­gle WXY –>  1/2 × 3z × 1.5= 2.25 z² cm²

2.25 z² × 2 = 4.5z² cm²

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