Tag Archives: problem sums

Primary 4 April Problem Sums 5

P4-PSP-Apr-Ex5

Ans:

1–  2822 peo­ple

243 × 4 = 972 men

972 + 243 = 1215 adults

1215 + 392 = 1607 children

1607 + 1215 = 2822 peo­ple

 

2–  131 coins

2389 + 2531 = 4920 ( total num­ber of coins)

Qn 2

4920 — 120 = 4800

4800 ÷ 2 = 2400 ( Num­ber of coins in Box B at the end)

2531 — 2400 = 131 coins

 

3–  $1368

One blouse –>  $19 × 3 = $57

$57 × 24 = $1368

Con­tinue read­ing

  

Primary 5 April Problem Sums 2

P5-Apr-PSP-Ex 2

Ans:

1–  12 l

2–  $114

Qn 2

 

1u ->  $36 — $15 = $21

Stella (at first) –>  $21 + $36 = $57

$57 × 2 = $114

 

3–  8th day

1st and 2nd day ->  1/12 + 1/6 = 1/4 of his money

4/4 — 1/4 = 3/4 of his money left after the 2nd day.

3/4 ÷ 1/8 = 6 days

6 + 2 = 8 days

Con­tinue read­ing

  

Primary 6 April Problem Sums 4

P6-PSP-Apr-Ex 4

Ans:

1–  Richard  ->  $74  ,   Louis  -> $13

Total amount of money in the end– >  $87 + $17 = $104

Richard  :  Louis
7         : 1

8u  –>  $104
1u  –>  $13 (Louis)

$13 × 7 = $91

$91 — $17 = $74 (Richard)

 

2–  $94 146

4   1/2 years  ->  54 months

54 × $1299 = $70 146

$70 146 + 20 000 + 4000 =  $94 146

Con­tinue read­ing

  

Primary 4 April Problem Sums 4

P4-PSP-Apr-Ex4

Ans:

1–  $50

Doc4

 

44 × 5 = $220

$292 — $220 = $72

$72 ÷ 12 = $6 (bulb)

$6 + $44 = $50

 

2–  76 316 more men

80 176 — 79 404 = 772 children

772 × 3 =  2316 women

79 404 — 2316 = 77 088 men

77 088 — 772 = 76 316 more men

Con­tinue read­ing

  

Primary 5 April Problem Sums 1

P5-Apr-PSP-Ex 1

Ans:

1–  5   2/15 m

2  4/5 m + 2  1/3 m = 5   2/15 m

 

2–  $14

Total he spent ->  $40 — $5 = $35

Mag -> 1 unit

Book ->  2 units

3 mags + 1 book -> 5u

5u –> $35

1u ->  35 ÷ 5 = $7

2u -> $7 × 2 = $14

Con­tinue read­ing

  

Primary 4 March Problem Sums 4

P4-PSP-Mar-Ex4

Ans:

1–  $5728

2–  3476 apples

3–  300 swimmers

4–  a ->  1/2 ,   b -> 1/2

5–  389 pack­ets of rice

6–  600 stamps

7–  $800

8–  a ->  384 pies ,   b ->  64 pies

9–  a ->  450 cook­ies  ,   b ->  530 cookies

10–  a ->  60 books ,   b ->  160 books

11–  750 pies

12–  $32

  

Primary 5 March Problem Sums 3

P5-PSP-Mar-Ex3

Ans:

1–  128 cm

2–  $128 more

3–  160 marbles

4–  9800 more Eng­lish books

5–  3360 pupils

6–   14 exer­cise books

7–  54 years’ time

8–  10.5 kg

9–  270 cookies

10–  a ->  Feb­ru­ary ,   b -> $175

11–  $1000

12–  $380

13–  $222

14–  $1020

15–  3374 more children

16–  144 marbles

17–  30 mangoes

18–  111 more puppies

  

Primary 6 March Problem Sums 6

P6-PSP-Mar-Ex6

Ans:

1–  $2.50

2–  (2+ 7) years

3–  119.2 m

4–  $3.50

5–  $40

6–  32 marbles

7–  75.75 cm²

8–  $3600

9–  See attached Qn 9

10–  a ->  445 parcels ,   b -> $2225

11–  $75

12–  $70

13–  $1056

14–  80 cm

15–  175 ml

16–  204 balloons

17–  27 cor­rect answers

18–  $31

 

  

Primary 4 March Problem Sums 1

P4-PSP-Mar-Ex3

Ans:

1–  60 stamps

2–  $75

3–    72

4–  $980

5–  9272 people

6–  3   1/6 kg

7–  $58

8–  160 pages

9–  17   5/6 cm

10–  a ->  48 T-shirts ,   b -> $240

11–  42 brownies

12–  $56

13–  180 cards

14–  38 passengers

15–  a ->  $20 ,   b -> $120

16–  $232

  

Primary 6 CA1 Revision 12

P6-CA1-Ex12

Ans:

1–  2.5 kg

2–  343 cm³

3–  24 red marbles

4–  $17.40

5–  102 students

6–  12 days

7–  232 cm²

8–  a ->  Tue and Fri ,   b — >  Thur ,   c -> 174

9–  57 marks

10– 24 pencils

11–  1/8

12–  a ->  135° ,   b -> 70°

13–  156 children

14–  a ->  37 dots  ,   b ->  170 dots

15–  1 : 1

16–  a ->  448 oranges  ,   b ->  192 pears and mangoes

17–  200 chicken pies

18–  a ->  480 straw­berry tarts ,   b -> $234