Tag Archives: Primary 4

Primary 4 March Review 4

P4-Mar-Review 4

Ans:

1–  2

2–  3

3–  3

4–  2

3   2/3 = 11/3 = 22/6

 

5–  1

Total number of tourists –>  180 + 160 + 220 + 140 + 220 = 920

140/920 = 7/46

 

6–  3

Fraction of money Charmaine saved ->  8/8 – 3/8 = 5/8

5/8 × $7208 = $4505

 

7–  4

Length of each ribbon –>  3/12 = 1/4 m

1/4  × 5 = 5/4 = 1  1/4 m

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Primary 4 CA1 Revision 4

P4-CA1-Ex 4

Ans:

1–  2

2–  4

3–  4

4–  4

5–  4

6–  2

7–  4

3000 + 78 230 = 81 230 = 75 thousands, 62 hundreds, 30 ones

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Primary 4 CA2 Revision 3

P4-CA2-Ex 3

Ans:

1–  376 women
Qn 1

 
11u –>  2068

1u –>  188

188 × 2 = 376 women

 

2–  $49

Cost of 25 crates of apples –>  $58 × 25 = $1450

Cost of 3 crates of oranges —  $1597 – $1450 = $147

$147 ÷ 3 = $49

 

3–  $17

Cost of 6.5 kg of prawns –>  $24 × 6.5 kg = $156

Cost of 2 kg of fish –>  $190 – $156 = $34

$34 ÷ 2 = $17 

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Primary 4 CA2 Revision 2

P4-CA2-Ex 2

Ans:

1– 152.35

2–  2  1/4

3–  15 013

4–  22   1/50

5–  See below

Qn 5

 

 

 

 

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Primary 4 CA2 Revision 1

P4-CA2-Ex 1

Ans:

1–  3

2–  4

3–  3

4– 4

5–  2

29/50 + 7/100
= 58/100 + 7/100 = 65/100 = 0.65

 

6–  3

7–  1

1/3 ≈ 0.333

0.33 = 0.330

0.330 is smaller than 0.333

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Primary 4 June Review 1

P4-June-Review 1

Ans:

1–  3

2–  3

3–  2

4–  4

5–  4

6–   4

7–  4

Lisa –>  4u

Michelle –>  5u

4u –>  60 marks

1u –>  15 marks

15 marks × 5 =  75 marks

 

8–  2

Joshua’s age –>  36 + 3  3/5 = 39  3/5 years old

39   3/5 – 5  3/10 = 34  3/10 years old×

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Primary 4 SA1 Revision 5

P4-SA1-Ex 5

Ans:

1–  Twelve thousand, seven hundred and ninety-eight

2–  2568

3–  1885 / 1886 /1887 /1888/1889/1891/1892/1893/1894

4–  5/9

5–  875

6–  761

        761          ,        12 870     ,     24 969      ,     37 058    ,    49 137
( +12 109)     (+ 12 099)      (+ 12 089 )     (+ 12 079)

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Primary 4 March Problem Sums 5

P4-PSP-Mar-Ex 5

Ans:

1–  $96

2–  28 sweets

Qn 2

If 1 add 12 more sweets to Jacqueline, she will have 1 unit.

4u –>  100 + 12 = 112

112 ÷ 4 = 28 sweets

 

3–  a ->  $8250   b ->  $2475

Amount of money Melanie spent in January –>  $825 × 2 = $1650

$1650 × 5 = $8250          (a)

$825 + $1650 = $2475      (b)

 

4–  5/8 m

5– 1175 stamps

Roger –>  1u

Joshua –>  4u

4u – 1u = 3u

3u –>  705 stamps

1u –>  235 stamps

235 × 5u = 1175 stamps

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Primary 4 February Review 5

P4-Feb- Review 5

Ans:

1–  4

2–  4

3–  2

1 whole –>   4 quarters

4 quarters × 3 = 12 quarters

 

4–  3

5–  2

4 = 36/9

38/9  –  36/9  =  2/9

 

6–  2

7–  2

Sharon’s mass ->  (64 – 8)/2 = 28 kg

Susan’s mass 28 kg + 8 kg = 36 kg

28/36  =  7/9

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Primary 4 October Problem Sums 4

P4-Oct-PSP-Ex 4

Ans:

1–  208 chicken pies

2–  17  1/3 kg

3–  $144

Qn

 

1u –>  $36 + $36 = $72

$72 × 2 = $144

 

4–  7 cm

Area of big rectangle –>  14 cm × 9 cm = 126 cm²

Area of unshaded rectangle –>  126 cm² – 98 cm² = 28 cm²

Length of AB –>  28 cm² ÷ 4 cm = 7 cm

 

5–  35 minutes

Time the piano lesson ended —>  1h 40 min after 11 30 –>  13 10

Time duration between 13 10 and 13 45 —>  35 minutes

 

6–  32.5 kg

Alison + Brenda –>  61.5 kg
Alison + Christine –>  67 kg
Brenda + Christine –>  63.5

61.5 kg + 67 kg + 63.5 kg = 192 kg

A + A + B + B + C + C –>  192 kg

A + B + C –>  192 kg ÷ 2 = 96 kg

96 kg – 63.5 kg = 32.5 kg

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