Tag Archives: mcq

Primary 5 CA2 Revision 1

P5-CA2-Ex 1

Ans:

1–  3

2–  1

3–  2

Area of square –>  8 cm × 10 cm = 80 cm²

Base of tri­an­gle –>  14 cm — 8 cm = 6 cm

Area of tri­an­gle –>  1/2 × 6 cm × 10 cm = 30 cm

80 cm + 30 cm = 110 cm²

 

4–  3

5–  2

1 hour –> 60 min × 60 = 3600 sec

3600/100 = 36 sets of 100 seconds

36 × 10 = 360 lol­lipops

 

6–  2

11.00 a.m. to 12 p.m. –> $2

12 p.m. to 2.30 p.m. –>  2.5 hours ≈ 3 hours –> 3 × $1 = $3

$3 + $2 = $5

Con­tinue read­ing

Primary 4 CA2 Revision 1

P4-CA2-Ex 1

Ans:

1–  3

2–  4

3–  3

4– 4

5–  2

29/50 + 7/100
= 58/100 + 7/100 = 65/100 = 0.65

 

6–  3

7–  1

1/3 ≈ 0.333

0.33 = 0.330

0.330 is smaller than 0.333

Con­tinue read­ing

Primary 6 Prelims Revision 6

P6-Prelims-Ex 6

Ans:

1–  $1225

18% = 9/50

90% = 9/10

There­fore,

Bran­don   :   Charles
50        :     10
5          : 1

6u –> $1470

1u –> $245

$245 × 5u = $1225

 

2–  9/10 h

Time taken to fill 1/9 of the tank –>  2/5 ÷ 4 = 1/10 h

1/10 h × 9 = 9/10 h

 

3–  8 pen­tagons

3 × 5 = 15 match­sticks for the 3 extra pentagons

60 — 15 = 45 match­sticks (The num­ber of squares and pen­tagons are now the same)

Num­ber of match­sticks needed to make 1 square and 1 pen­ta­gon -> 4 + 5
= 9

45/9 = 5

5 + 3 = 8 pen­tagons

 

4–  10 hours

55 min = 11/12 h

11/12 h + 3/4 h = 1   2/3 h

5  1/2 h ÷ 11/12 h = 6 sets

6 × 1   2/3 h = 10 hours

 

5–  $40

85% — 55% = 30%

30% –> $12

100% –>  12/30 × 100 = $40

Con­tinue read­ing

Primary 3 Length, Mass and Volume Level 1 Ex 1

P3-Length, Mass and Volume-L1-Ex 1

Ans:

1–  1

2–  3

3–  3

4–  2

5–  2

6–  4

7–  2

8– 2

Mass of apple –>  640 g ÷ 4 = 160 g

160 g + 640 g = 800 g

Con­tinue read­ing

Primary 3 SA1 Revision 7

P3-SA1-Ex 7

Ans:

1–  4

2–  3

3–  1

4–  1

Odd num­bers between 5 and 15 –>  7, 9, 11, 13

7 + 9 + 11 + 13 = 40

 

5–  2

6–  4

7–  2

8–  3

9–  2

10–  4

7 × 9 = 63

63 ×  = 189

Con­tinue read­ing

Primary 6 SA1 Revision 10

P6-SA1-Ex 10

Ans:

1–  3

2–  3

3–  4

2u –> 18 cm

1u –>  9 cm

Length –>  9 cm × 3u = 27 cm

Perime­ter –>  (18 + 27) cm × 2 = 90 cm

 

4–  2

5–  2

6–  3

Frac­tion of remain­ing cake –> 5/6

5/6 ÷ 1/12 = 10 pupils

Con­tinue read­ing

Primary 5 Ratio Level 1 Ex 5

P5-Ratio-L1-Ex 5

Ans:

1–  2

2–  4

3–  3

Local   :   For­eign
3        : 5

3u + 5u = 8u

8u –>  120 stamps

1u –>  120/8 = 15 stamps

15 × 3 = 45 local stamps

 

4–  3

5–  3

Perime­ter –>  Length + Breadth + Length + Breadth
->     3u        +    1u         +    3u       +      1u  = 8u

8u –> 40 cm

1u –>  40/ 8 = 5 cm

5 cm × 3 = 15 cm

 

6–  3

Son’s age –>  42 — 28 = 14 years old

42  :  14 =  3  : 1

Con­tinue read­ing

Primary 2 Whole Numbers Level 1 Ex 2

P2-Whole Numbers-L1-Ex 2

Ans:

1–  3

2–  3

3–  1

4–  3

5–  3

6–  2

7 hun­dreds 8 tens 12 ones –> 792

1 hun­dred 2 tens 2 ones –> 122

792 — 122 =  670 

Con­tinue read­ing

Primary 2 Whole Numbers Level 1 Ex 1

P2-Whole Numbers-L1-Ex 1

Ans:

1–  1

2–  3

3–  2

1 rec­tan­gle –>  16 ÷ 2 = 8

8 + 3 = 11

 

4–  3

9 + 3 + 9 + 3 = 24

24 ÷ 4 = 6

 

5–  2

6–  4

7–   Con­tinue read­ing

Primary 6 Algebra Level 1 Ex 4

P6-Algebra-L1-Ex 4

Ans:

1–  1

2–  1

3–  4

12x + 19 + (4x × 6 ÷ 3) – 8
= 12x + 19 + 8x - 8 = 20x + 11

 

4–  2

5–  2

Amount left after giv­ing her daugh­ter —  $(800 — 40z)

Each son ->  $(800 — 40z) ÷ 3

Con­tinue read­ing