Tag Archives: Maths

Primary 4 March Problem Sums 5

P4-PSP-Mar-Ex 5

Ans:

1–  $96

2–  28 sweets

Qn 2

If 1 add 12 more sweets to Jacque­line, she will have 1 unit.

4u –>  100 + 12 = 112

112 ÷ 4 = 28 sweets

 

3–  a ->  $8250   b ->  $2475

Amount of money Melanie spent in Jan­u­ary –>  $825 × 2 = $1650

$1650 × 5 = $8250          (a)

$825 + $1650 = $2475      (b)

 

4–  5/8 m

5– 1175 stamps

Roger –> 1u

Joshua –> 4u

4u — 1u = 3u

3u –>  705 stamps

1u –>  235 stamps

235 × 5u = 1175 stamps

Con­tinue read­ing

  

Primary 3 March Review 4

P3-Mar-Review 4

Ans:

1–  3

2–  2

3–  1

4–  1

5–  3

6–  2

7–  4

Num­ber of stamps Javier had –>  135 × 6 = 810

810 + 135 = 945 stamps

Con­tinue read­ing

  

Primary 6 March Review 7

P6-Mar-Review 7

Ans:

1–  3

2–  4

3–  4

3.30 p.m. to 4.30 p.m. –>  1st hour –> $3.50

4.30 p.m. to 5.45 p.m.–>  1 h 15 min ->  3 sets of half-hours
->  3 × $1 = $3

$3.50 + $3 = $6.50

 

4–  1

5–  2

6–  3

7–  2

75% — 50% = 25%

25% –>  105 ml

50% –>  105 ml × 2 = 210 ml

Con­tinue read­ing

  

Primary 5 March Review 3

P5-Mar-Review 3

Ans:

1–  3

2–  3

4  1/4 = 17/4

17/4 = 34/8

 

3–  4

4–  2

Length of String Q –>  3  1/5 m —  1  2/3 m = 1  8/15 m

1  8/15 m + 3  1/5 m = 4  11/15 m

 

5–  2

Remain­ing pizza after Joseph had eaten it –>  8/8 — 1/8 = 7/8

4/5 × 7/8 = 7/10

 

6–  1

Breadth of rec­tan­gle–>  (48 cm÷ 2) — 14 cm = 10 cm

14 cm × 10 cm = 140 cm²

 

7–  2

8–  2

(24 sweets  cost the same as 18 choco­lates )  ÷ 3

8 sweets cost the same as 6 chocolates

18 — 6 = 12 choco­lates 

Con­tinue read­ing

  

Primary 4 February Review 5

P4-Feb– Review 5

Ans:

1–  4

2–  4

3–  2

1 whole –>   4 quarters

4 quar­ters × 3 = 12 quar­ters

 

4–  3

5–  2

4 = 36/9

38/9  -  36/9  =  2/9

 

6–  2

7–  2

Sharon’s mass ->  (64 — 8)/2 = 28 kg

Susan’s mass 28 kg + 8 kg = 36 kg

28/36  =  7/9

Con­tinue read­ing

  

Primary 3 CA1 Revision 5

P3-CA1-Ex 5

Ans:

1–  6854

2–  2664

3– 2790

4–  8791

5–  4000

6480 — 2394 = 4086

80 + 6 = 86

4086 — 86 = 4000

 

6–  9731

8731 + 1000 = 9731

Con­tinue read­ing

  

Primary 2 Whole Numbers Level 1 Ex 2

P2-Whole Numbers-L1-Ex 2

Ans:

1–  3

2–  3

3–  1

4–  3

5–  3

6–  2

7 hun­dreds 8 tens 12 ones –> 792

1 hun­dred 2 tens 2 ones –> 122

792 — 122 =  670 

Con­tinue read­ing

  

Primary 6 Algebra Level 2 Ex 5

P6-Algebra-L2-Ex5

Ans:

1–  $(7y/2) /  $3.50y

Price of 1 durian –>  $(y/10)

$(y/10) × 35 = $(7y/2)/ $3.50y

 

2–  55

3–  (35 

4–  (4+ 10) years old

Brother’s age –>  3n + 9 — 2n = (n + 9) years old

Total age now –>  3n + 9 + n + 9 = 4n + 18 years old

4n + 18 – 4 – 4 = (4n + 10) years old

 

5–  $(m – 20)/3

6–  4.5z² cm²

Area of Tri­an­gle WXY –>  1/2 × 3z × 1.5= 2.25 z² cm²

2.25 z² × 2 = 4.5z² cm²

Con­tinue read­ing

  

Primary 3 Whole Numbers Level 3 Ex 4

P3-Whole Numbers-L3-Ex 4

Ans:

1–  4200 beads

Qn 1

Num­ber of beads Jen­nifer has –>  1866 + 468 = 2334

2334 + 1866 = 4200 beads

 

2–  195 steps

3–  67 cook­ies

4–  a –>  1277 men   ,   b ->  1085 more men

Num­ber of men who par­tic­i­pated –>  1277 — 89 = 1188

Num­ber of women who par­tic­i­pated –>  123 — 20 = 103

1188 — 103 =1085 more men 

 

5–  5460 stick­ers 

Num­ber of months from Feb­ru­ary to Octo­ber –> 9

9 × 20 = 180 more than January

5280 + 180 = 5460 stick­ers

 

6–  $712

Total amount of money Melody and Lisa have –>  $2835 + $4259 = $7094

Amount of money each of them has in the end –>  $7094 ÷ 2 = $3547

$4259 — $3547 = $712

Con­tinue read­ing

  

Primary 2 Whole Numbers Level 1 Ex 1

P2-Whole Numbers-L1-Ex 1

Ans:

1–  1

2–  3

3–  2

1 rec­tan­gle –>  16 ÷ 2 = 8

8 + 3 = 11

 

4–  3

9 + 3 + 9 + 3 = 24

24 ÷ 4 = 6

 

5–  2

6–  4

7–   Con­tinue read­ing