Tag Archives: heuristic

Primary 6 August Problem Sums 9

P6-PSP-Aug-Ex 9

Ans:

1– 28 cm

Square num­bers are 1, 4, 9, 16, 25, 36, 49, 64, 81, etc …

The two pos­si­ble square num­bers that add to 74 are 25 and 49

5 cm × 5 cm = 25 cm²

7 cm × 7 cm = 49 cm²

7 cm × 4 = 28 cm

 

2–  355 more marbles

Num­ber of boys –>  3 + 5 = 8

Units of mar­bles each girl received –> 1u

Units of mar­bles each boy received –>  1u + 30

Total received by the 8 chil­dren –>  1u × 3 + (1u + 30) × 5 = 8u + 150

8u + 150 mar­bles ->  570 marbles

8u –>  570 — 150 = 420 marbles

1u –>  102.5 marbles

(5u + 150) — 3u = 2u + 150

(102.5 × 2) + 150 = 355 more marbles

 

3–  $71.50

7 duri­ans + 10 man­goes –> $57

[1 durian + 1 mango –>  $7.50] × 7
–>  7 duri­ans + 7 man­goes –>  $52.50

There­fore, $57 — $52.50 = $4.50 –>  3 mangoes

1 mango–>  $4.50/ 3 = $1.50

1 durian –>  $7.50 — $1.50 = $6

4 duri­ans + 3 man­goes –>  $6 × 4+ $1.50 × 3 = $28.50

$100 — $28.50 = $71.50

 

4–  15 : 6 : 10

Red   :  Blue                      Blue   :   Pur­ple
5      :     2                             3      : 5

–>  15    :     6                             6      : 10

Red   :   Blue   :   Pur­ple
15   :    6    : 10

 

5–  56 cm

Height of water level at first –>  5/8 × 64 cm = 40 cm

1600 cm³ ÷ (10 × 10) cm² = 16 cm

16 cm + 40 cm = 56 cm

 

6–  200 cook­ies

[Con­stant Difference]

At first:

Joanna –>  250 cookies

Sharon ->  350 cookies

In the end –>        Joanna  :  Sharon
3       : 5

2u –> 100

1u –> 50

8u –>  50 × 8 = 400 cook­ies left

600 — 400 = 200 cook­ies

 

7–  $13.50

5 small tow­els + 6 big tow­els –>  $34.50

6 small tow­els + 5 bog tow­els –>  $34.50 — $4 = $31.50

11 small tow­els + 11 big tow­els –>  $34.50 + $31.50 = $66

1 small towel + 1 big towel –> $66/ 11 = $6

5 small tow­els + 5 big tow­els –>  $6 × 5 = $30

1 big towel –> $34.50 — $30 = $4.50

$4.50 × 3 = $13.50

Con­tinue read­ing

Primary 6 Prelims Revision 9

P6-Prelims-Ex 9

Ans:

1– $45

Julian –> 1u

Fred­er­ick –> 2u

Mar­cus –> 6u

5u –> $25

1u –> $5

$5 × 9u = $45

 

2–  16 more tricycles

Assume all are tri­cy­cles –> 56 × 3 = 168 wheels

168 — 148 = 20 wheels extra

Each bicy­cle has 1 lesser wheel than each tricycle.

There­fore, 20 ÷ 1 = 20 bicycles

56 — 20 00= 36 tricycles

36 — 20 = 16 more tri­cy­cles than bicycles

 

3–  $44

4–  22.5 km/h faster

Mar­cus’ speed –>  270 /4 = 67.5 km/h

Mar­cus’ new speed –>  270/3 = 90 km/h

90 km/h — 67.5 km/h = 22.5 km/h faster

 

5–  396 boys

Girls –>  1u × 5 = 5u

Boys –>  (1u + 16) × 3 = 3u + 48

8u + 48 –>  976 pupils

8u –> 928

1u –> 116

116 × 3 + 48 = 396 boys

 

6–  $2945

7 hand­bags + 5 watches = 3 hand­bags + 11 watches

7 hand­bags — 3 hand­bags = 11 watches — 5 watches

4 hand­bags = 6 watches

6 watches –>  $285 × 4 = $1140

1 watch –>  $1140 ÷ 6 = $190

$285 × 7 + $190 × 5 = $2945

 

7–  300 stick­ers

Maxwell –> 100%

Jeanet­ter –> 120%

20/100 × 120% = 24%

120%  - 24% = 96% left

96% –>  288 stickers

1% — 3 stickers

3 × 100 = 300 stick­ers

 

8–  153 cm

17 + 13 = 30 cm — 3 pieces

1 piece –>  10 cm

14 × 10 cm + 13 cm = 153 cm

Con­tinue read­ing

Primary 6 Prelims Revision 8

P6-Prelims-Ex 8

Ans:

1–  966

Low­est com­mon mul­ti­ple of 2, 3 and 7 –> 42

999 ÷ 42 = 23 R 33

23 × 42 = 966

 

2–  75%

3–  Thou­sandths

4–  12- 7

5–  28%

6–  $6000

7–  $2375

8–  94 marks

Total marks for the 3 tests –>  79 marks × 3 = 237

237 — 69 — 74 = 94 marks

Con­tinue read­ing

Primary 6 Prelims Revision 3

P6-Prelims-Ex 3

Ans:

1–  3 : 12 : 17

2–  4.95 cm

Length of the tank –>  180 cm³ ÷ 12 edges = 15 cm

33/100 × 15% = 4.95 cm

 

3–  100 balls

Total units of balls –>  5u + 4u = 9u

Units of balls in each bag in the end –>  9u/2 = 4.5u

5u — 4.5u = 0.5u —>  10 balls

1u –>  10 × 2 = 20 balls

20 × 5u = 100 balls

 

4–  540 km

5–  $24

1 blouse –> 1u

1 pair of jeans –>  1u + $12

3 pairs of jeans + 4 blouses –>  (1u + $12) × 3 + 4u = 7u + $36

7u + $36 -> $204

7u –>  $204 — $36 = $168

1u –>  $24

 

6–  891 beads

Red : Blue + Green
4   : 5

Blue : Green
3    :    8     –> 11u

Adjust the units for the blue and green beads such that they are the same in both cases.

Com­mon mul­ti­ple of 5 and 11 is 55u

There­fore,

Red  :  Blue + Green
44   : 55

Blue  :  Green
15   : 40

Red  :  Blue  :  Green
44 :    15   : 40

44u — 40u = 4u –>  36 beads

1u –>  9 beads

44u + 55u = 99u —->  9 beads × 99 = 891 beads

Con­tinue read­ing

Primary 6 SA1 Revision 12

P6-SA1-Ex 12

Ans:

1–  175

2–  $43.50

70% of the price –>  $101.50

30% –>  $101.50/70 × 30 = $43.50

 

3–  (3+ 6) kg

Alan’s mass ->  (+ 3) kg

Nicholas’ mass ->  (m + 3) — 2 = (+ 1) kg

Brett’s mass ->  (+ 1) + 1 = (+ 2) kg

(m + 3) + (+ 1) + (+ 2) = (3+ 6) kg

 

4–  195 km

1  1/2 h× 80 km/h = 120 km

45/60 h × 100 km/h = 75 kg

120 km + 75 km = 195 km

 

5–  $6441.60

Earn­ings in Jan­u­ary –>  122/100 × $6000 = $7320

Earn­ings in Feb­ru­ary –>  88/100 × $7320 = $6441.60

 

6–  30 peo­ple

Frac­tion of men  –>  30/100 = 3/10 = 9/30

Frac­tion of men if 10 women alighted –>  45/100 = 9/20

Women –>  30u — 9u = 21u

20u — 9u = 11u

10u –>  10 women

30 u –>  30 people

Con­tinue read­ing

Primary 6 April Problem Sums 5

P6-PSP-Apr-Ex 5

Ans:

1–  30 m

Spaces between 100 trees –> 99

Dis­tance between each tree –> 297 m ÷ 99 = 3 m

3 m × 10 spaces = 30 m

 

2–  28 pupils

Num­ber of pupils who passed one or both sub­jects –> 40 — 2 = 38

30 + 36 = 66

66 — 38 = 28 pupils

 

3–  a ->  (18s + 24) kg ,   b ->   16 kg

Mass of chicken –>  3s kg

Mass of puppy –>  (3s + 4) kg

Mass of dog –>  (3+ 3s + 4) kg × 2 = (12+ 8) kg

3s + 3s + 4 + 12s + 8 = (18s + 12) kg                   (a)

18 × 2 + 12 = 48 kg

48 kg ÷ 3 = 16 kg                           (b)

 

4–  $51.30

Total cost of 5 apples and 5 man­goes –>  $3.25 × 5 = $16.25

Cost of 3 apples –>  $17.60 — $16.25 = $1.35

Cost of 1 apple –> $1.35 ÷ 3 = $0.45

Cost of 1 mango –> $3.25 — $0.45 = $2.80

Cost of 2 man­goes and 7 apples –>  $2.80 × 2 + $0.45 × 7 = $8.70

$50 — $8.70 = $51.30

Con­tinue read­ing

Primary 4 March Problem Sums 5

P4-PSP-Mar-Ex 5

Ans:

1–  $96

2–  28 sweets

Qn 2

If 1 add 12 more sweets to Jacque­line, she will have 1 unit.

4u –>  100 + 12 = 112

112 ÷ 4 = 28 sweets

 

3–  a ->  $8250   b ->  $2475

Amount of money Melanie spent in Jan­u­ary –>  $825 × 2 = $1650

$1650 × 5 = $8250          (a)

$825 + $1650 = $2475      (b)

 

4–  5/8 m

5– 1175 stamps

Roger –> 1u

Joshua –> 4u

4u — 1u = 3u

3u –>  705 stamps

1u –>  235 stamps

235 × 5u = 1175 stamps

Con­tinue read­ing

Primary 3 Whole Numbers Level 3 Ex 4

P3-Whole Numbers-L3-Ex 4

Ans:

1–  4200 beads

Qn 1

Num­ber of beads Jen­nifer has –>  1866 + 468 = 2334

2334 + 1866 = 4200 beads

 

2–  195 steps

3–  67 cook­ies

4–  a –>  1277 men   ,   b ->  1085 more men

Num­ber of men who par­tic­i­pated –>  1277 — 89 = 1188

Num­ber of women who par­tic­i­pated –>  123 — 20 = 103

1188 — 103 =1085 more men 

 

5–  5460 stick­ers 

Num­ber of months from Feb­ru­ary to Octo­ber –> 9

9 × 20 = 180 more than January

5280 + 180 = 5460 stick­ers

 

6–  $712

Total amount of money Melody and Lisa have –>  $2835 + $4259 = $7094

Amount of money each of them has in the end –>  $7094 ÷ 2 = $3547

$4259 — $3547 = $712

Con­tinue read­ing

Primary 5 October Problem Sums 5

P5-PSP-Oct-Ex5

Ans:

1–  $6588

2–  2400 cm³

Amount of water at first –>  4/5 × 30 cm × 20 cm × 30 cm = 14 400 cm³

Amount of water in the end –>  2/3 × 30 cm × 20 cm × 30 cm = 12 000 cm³

14 400 cm³ — 12 000 cm³ = 2400 cm³

 

3–  38 mar­bles

Qn 3

2u –>  96 — 60 = 36

Barry –>  36 ÷ 2 = 18 marbles

Joe –>  60 — 18 = 42 marbles

Tom –>  18 × 3 = 54 marbles

Total –> 54 + 42 + 18= 114 marbles

114 ÷ 3 = 38 mar­bles

 

4–  Cup Y —  160 ml    ,   Cup Z —  60 ml

Y   :   Z
8   : 3

8u + 3 = 11u

11u ÷ 2 = 5.5u

8u — 5.5u = 2.5u

2.5u –>  50 ml

1u –>  20 ml

Cup Y –>  20 ml × 8u = 160 ml

Cup Z –>  20 ml × 3 = 60 ml

 

5–  $651.80

Qn 5

2u –>  $1505 — $201.40 = $1303.60

$1303.60 ÷ 2 = $651.80

 

6–  $15.50

Qn 6

 

2u–  $108 — $71 = $37

1u —  $18.50

Megan –> $18.50 × 3 = $55.50

$71 — $55.50 = $15.50

Con­tinue read­ing

Primary 6 September Problem Sums 10

P6-PSP-Sep-Ex 10

Ans:

1–  See below

Qn 1

 

2–  9360 cm³

Height of water needed to fill the con­tainer –>  25 cm — 18.5 cm = 6.5 cm

45 cm × 32 cm × 6.5 cm = 9360 cm³

 

3–  68 but­tons

36 + 3 = 39 more buttons

8 — 5 = 3  buttons

∴ She needs 39 more but­tons because she is putting 3 more but­tons into each box.

39 ÷ 3 = 13 boxes

13 × 5 + 3 = 68 but­tons

 

4–  $580

107% –>  $465.45

100% –>  $435 (dis­counted price with­out GST)

75% –> $435

100% –>  435/75 × 100 = $580

 

5–  136 chil­dren

40% = 40/100 = 2/5

2/3 of the boys = 2/5 of the girls

Boys  :  Girls
3      : 5

2u –> 34

1u –> 17

17 × 8 = 136 chil­dren 

Con­tinue read­ing