Primary 4 August Review 4

P4-Aug-Review 4

Ans:

1–  3

2–  3

3–  2

4–  4

5–  4

7.25 a.m. to 9.25 a.m (2 hour) –>  8 quarter-turns

8.25 a.m. to 9.40 a.m. (15 min) –>  1 quar­ter turn

8 + 1 =

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Primary 3 Fractions Level 1 Ex 1

P3-Fractions-L1-Ex1

Ans:

1–  4

2–  2

3–  4

4/16 = 1/4

 

4–  1

5–  3

6–  2

7–  1

Total num­ber of daisies –>  2 + 3 + 4 = 9

3/9 = 1/3 

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Primary 6 August Review 6

P6-Aug-Review6

Ans:

1–  4

2–  1

Total of the 4 num­bers –>  4 × 22 = 88

88 — 24 — 26 — 28 = 10

 

3–  1

4–  4

15/60 × 300 km = 75 km

75 km = 75 000 m

 

5–  4

6–  4

5/5 — 2/5 = 4/5  (owned cats and dogs)

3/5 –>  48 + 72 = 120 children

1/5 –>  40 children

5/5 –>  40 × 5 = 200 chil­dren

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Primary 5 Average Level 3 Ex 4

P5-Average-L3-Ex4

Ans:

1–  432 more stamps

Total num­ber of stamps Jamie and Patrick had ->  360 × 2 = 720

Patrick -> 1u

Jamie -> 4u

5u –>  720 stamps

1u –>  144 stamps

4u — 1u = 3u

3 × 144 = 432 more stamps

 

2–  71.5 kg

Total mass of 3 boys if they weigh as much as Derek –>  75 × 3 + 12 + 9 = 246 kg

Derek’s mass  –>  246 kg ÷ 3 = 82 kg

Joe’s actual mass ->    82 kg — 12 kg = 70 kg

Ron’s actual mass ->  82 kg — 9 kg = 73 kg

Aver­age mass of Joe and Ron –>  (70 + 73) ÷ 2 =  71.5 kg

3–  5.8 m

Total mass of the pole, plank and rod –>  4.8 m × 3 = 14.4 m

Rod –> 1u

Pole –> 2u

Plank –>  2u + 0.4 m

5u +  0.4 m ->  14.4 m

5u –>  14.4 m — 0.4 m = 14 m

Rod  –>  14 m ÷ 5 = 2.8 m

Pole –>  2.8 m × 2 = 5.6 m

Plank –>  2.8 m × 2 + 0.4 = 6 m

Aver­age length of pole and plank –>  (5.6 m + 6 m ) ÷ 2 = 5.8 m

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Primary 4 July Problem Sums 3

P4-July-PSP-Ex 3

Ans:

1–  $9153

$2178 + $6975 = $9153

 

2–  5  5/12 kg

The total mass of the nails–>  9   11/12 kg —   11/12 kg = 9 kg

Mass of the nails when they are half-filled –>  9 /2 = 4   1/2 kg

4   1/2 kg +  11/12 kg = 5   5/12 kg

 

3–  3456 canned drinks

128 × 27 = 3456 canned drinks

 

4–  56.58 kg

Qn 4

6u –>  169.74 kg

1u –>  28.29 kg

28.29 kg × 2 = 56.58 kg

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Primary 3 Money Level 2 Ex 1

P3-Money-L2-Ex 1

Ans:

1–  $44

Amount of money she spent ->  $100 — $12 = $88

$88 ÷ 2 = $44

 

2–  3410¢

3–  $173.80

Cost of a fan ->  $99.85 — $25.90 = $73.95

Total cost –>  $99.85 + $73.95 = $173.80

 

4—  7 coins

5–  $5.55

6–  8 pack­ets 

Amount of money Janet spent -> $20 — $4  = $16

$16 ÷ $2 = 8 pack­ets 

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Primary 6 July Problem Sums 6

P6-July-PSP-Ex 6

Ans:

1–  $800

Frac­tion of money spent on food and shoes –>  1/4 + 1/5 = 9/20

20/20 — 9/20 = 11/20

11u –>  $340 + $100 = $440

1u –> $40

20u –>  $40 ×  20 = $800

 

2–  14 cook­ies

Muffins   :   Cookies

At first  ——>           [   5             :         6   ]  × 2

In the end   ——>    [   2             :        1  ]  × 5

[Make the units of muffins at first and in the end the same]

Muffins   :   Cookies

At first  ———>             10          : 12

In the end  ——->           10          : 5

12u –>  24 cookies

1u –>  2 cookies

5u –>  10 cook­ies left

24 — 10 = 14 cook­ies 

 

3–  Joseph spent more by $2000

3/5 of Terry’s money is equal to 1/3 of Joseph’s money.

[Make the numer­a­tor common]

3/5 of Terry’s is equal to  3/9 of Joseph’s.

Terry   :   Joseph
5         : 9

14u –> $7000

1u –> $500

Amount Terry spent –>  $500 × 5 = $2500

Amount Joseph spent –>  $500 × 9 = $4500

$4500 — $2500 = $2000

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Primary 5 Average Level 2 Ex 4

P5-Average-L2-Ex4

Ans:

1–  16

2–  242.2 m

0.96 km = 960 m

2.62 m + 2.08 m + 3.9 m + 960 = 242.15 m ≈ 242.2 m

 

3–  $75.90

4–  2 h 30 min

5250 ÷ 35 = 150 min

150 min= 2 h 30 min

 

5–  1.2 kg

10 kg 800 g = 10.8 kg

10.8 kg ÷ 9 = 1.2 kg

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Primary 4 July Problem Sums 2

P4-July-PSP-Ex 2

Ans:

1–  $144

1/2 u –> $36

1u –>  $36 × 2 = $72

$72 × 2 = $144

 

2–  $487.80

3–  6  4/5 kg

4–  2637 more seashells
Qn 4

7u –>  6328 — 623 = 5705

1u –> 815

Jan­ice –>  815 × 7 = 4075 seashells

Car­o­line –>  815 + 623 =1438 seashells

4075 — 1438 =  2637 more seashells

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Primary 3 July Review 1

P3-Jul-Review 1

Ans:

1–  3

2–  3

3–  2

4–  4

5–  4

6–  2

Grandmother’s age now —  9 × 9 = 81  Con­tinue read­ing

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